Answer: 5184 kJ
Explanation:
Given
Area of cross-section [tex]A=200\ cm^2[/tex]
thickness of slab [tex]t=5\ cm[/tex]
thermal conductivity [tex]k=0.5\ W/m-K[/tex]
temperature difference [tex]\Delta T=150\ K[/tex]
Heat flow is given by
[tex]\Rightarrow Q=kA\dfrac{dT}{dx}\\\Rightarrow Q=0.5\times 200\times \dfrac{150}{5}\times 10^{-2}\\\Rightarrow Q=30\ W\ or\ 30\ J/s[/tex]
for 2 days time period, it is
[tex]t=2\ days\ or\ 2\times 24\times 60\times 60\ s\\t=1,72,800\ s[/tex]
Heat flow in 2 days
[tex]Q=30\times 172800=5184000=5184\ kJ[/tex]
