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Connor has five nickels in one hand and some dimes in his other hand. He has more than two times as many dimes as nickels. He has fewer than three times as many dimes as nickels.

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Complete question :

How many dimes might he have?

How many coins would he have altogether?

Answer:

11, 12, 13, 14 ;

16, 17, 18, 19

Step-by-step explanation:

Let :

Nickel = n

Dimes = d

Total number of nickels = 5

He has more than 2 times as many dimes as nickels ;

d > 2n

d > 2*5 ; d > 10

He has fewer than 3 times as many dimes as nickels;

d < 3n

d < 3*5 ; d < 15

Meaning he has more than 10 dimes but less than 15.

10 < d < 15

So, d could be ;

11, 12, 13, 14

Number of coins altogether :

11 + 5 = 16

12 + 5 = 17

13 + 5 = 18

14 + 5 = 19

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