Answer:
21 feet
Step-by-step explanation:
Given :
Height of the tripod above the ground = 5 ft
Elevation = 8°
Distance of the tree from the tripod = 120 ft
Therefore from the figure, we can find the height of the tress as:
[tex]$\tan 8 ^\circ = \frac{BC}{AB}$[/tex]
[tex]$0.1405 = \frac{BC}{120}$[/tex]
∴  BC ≈ 16
Therefore, CE = BC+BE
            = 16 + 5
            = 21
Therefore the height of the tree is 21 feet.
The tree is 21.87 ft tall.
Kirsten's distance from the tree, D, the height of the tripod above the ground h and the line of sight of the top of the tree from the tripod form a right-angled triangle with hypotenuse side, Kirsten's line of sight, opposite side, height of the tripod above the ground and adjacent side, Kirsten's distance from the tree.
Since the angle of elevation above the horizontal of the top of the tree is 8°, we have that
tan8° = h/D
h = Dtan8°
Since D = 120 ft,
h = Dtan8°
h = 120tan8°
h = 120 × 0.1405
h = 16.87 ft
Since the tripod is 5 ft above the ground and the top of the tree is h = 16.87 ft above the top of the tripod, the height of the tree H = 5 + h
= 5 ft + 16.87 ft
= 21.87 ft
So, the tree is 21.87 ft tall.
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