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Assume a is a positive constant. Imagine solving for x (but do not actually do so). Will your answer involve logarithms?
a = log x

Assume a is a positive constant Imagine solving for x but do not actually do so Will your answer involve logarithms a log x class=

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sqdancefan

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Answer:

  (b)  No, 10^a is involved

Step-by-step explanation:

The relationship of interest is ...

  [tex]a=\log{(x)}\ \leftrightarrow\ 10^a=x[/tex]

Determining x involves the exponential 10^a.

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When faced with problems of this sort, I like to remind myself that a logarithm is an exponent.

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