Answer:
A
Explanation:
195.49 g K x 1 mole / 39.01 g x 6.022 x 10^23 atoms/mole = 30.11 x 10^23 = 3.011 x 10^24
The number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.
From the question,
We are to determine the number of K atoms present in 195.49 grams of K.
First, we will determine the number of moles K present
Using the formula,
[tex]Number\ of\ moles = \frac{Mass}{Atomic\ mass}[/tex]
Atomic mass of K = 39.0983 g/mol
Number of moles of K present = [tex]\frac{195.49}{39.0983}[/tex]
Number of moles of K present = 4.99996 moles
Number of moles of K present ≅ 5 moles
Now, for the number of atoms present
From the formula
Number of atoms = Number of atoms × Avogadro's constant
Number of K atoms present = 5 × 6.022 × 10²³
Number of K atoms present = 5 × 6.022 × 10²³
Number of K atoms present = 30.11 × 10²³
Number of K atoms present = 3.0110 × 10²⁴ atoms
Hence, the number of K atoms present in 195.49 grams of K is 3.0110 × 10²⁴ atoms. The correct option is a 3.0110 x 10²⁴.
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