Respuesta :
Answer:
[tex]SiO_{2}[/tex]
Explanation:
When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.
So:
53.3% = 53.3g O, 46.7% = 46.7g Si
The next step is to divide each mass by their molar mass to convert your grams to moles.
53.3g/15.99g = 3.33 mol
46.7g/28.08g = 1.66 mol
Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subscripts) of the empirical formula.
3.33 mol/1.66 = 2
1.66 mol/1.66 = 2
So the empirical formula is
[tex]SiO_{2}[/tex]
Considering the definition of empirical formula, the empirical formula is Si₁O₂= SiO₂.
The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.
Assuming a 100 grams sample, the percentages match the grams in the sample. So you have 53.3 grams of O and 46.7 grams of Si.
Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:
- O: [tex]\frac{53.3 g}{16\frac{g}{mole} }[/tex]= 3.33 moles
- Si: [tex]\frac{46.7 g}{28\frac{g}{mole} }[/tex]= 1.67 moles
The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:
- O: [tex]\frac{3.33 moles}{1.67 moles}[/tex]= 2
- Si: [tex]\frac{1.67 moles}{1.67 moles}[/tex]= 1
Therefore the Si: O mole ratio is 1: 2.
Finally, the empirical formula is Si₁O₂= SiO₂.
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