Answer:
T = 3.17 s
Explanation:
Given that,
The length of the pendulum, l = 2.5 m
We know that the period of oscillation of the pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
Where
g is the acceleration due to gravity
[tex]T=2\pi \sqrt{\dfrac{2.5}{9.8}}\\\\T=3.17\ s[/tex]
So, the period of oscillation is equal to 3.17 s.
