The circle below is centered at the point (8, 4) and has a radius of length 4. What is its equation?

Answer:
(x-8)^2 + (y-4)^2 = 16
Step-by-step explanation:
Standard equation of a circle is expressed as;
(x-a)^2 + (y-b)^2 = r^2
(a, b) is the centre
r is the radius
Given
Centre (8, 4)
r = 4
Substitute
(x-8)^2 + (y-4)^2 = 4^2
(x-8)^2 + (y-4)^2 = 16
This gives the required equation
Answer:
(x-8)^2 + (y-4)^2 = 16
Step-by-step explanation:
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