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Answer:
240
Step-by-step explanation:
1. Area of two small triangles (OR one big) + Area of rectangle
2. Triangle
A(t) = 4*10 = 40 [4*10/2 + 4*10/2]
3. Rectangle
A(r) = 20*10 = 200
4. Combined Area
40+200=240
Step-by-step explanation:
So this figure has two parts:- A triangle and a rectangle
We can first solve area of Triangle
[tex] = \frac{1}{2} bh[/tex]
So the base is 20 and height is 4
[tex] \frac{1}{2} \times 20 \times 4 \\ = 10 \times 4 \\ = 40[/tex]
Now the area of rectangle
[tex] = l \times b[/tex]
Length is 20 and breadth is 10
[tex]l \times b \\ 20 \times 10 \\ = 200[/tex]
So the total area is 200 + 40 which is equal to 240