A game of "Doubles-Doubles" is played with two dice. Whenever a player rolls two dice and both die show the same number, the roll counts as a double. If a player rolls doubles, the player earns 3 points and gets another roll. If the player rolls doubles again, the player earns 9 more points. Whenever the player rolls the dice and does not roll a double, they lose points. How many points should the player lose for not rolling doubles in order to make this a fair game? Now O 1 Mark this and return Save and Exit Next

Respuesta :

Answer:

27/35

Step-by-step explanation:

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The number of points that  should the player lose for not rolling doubles in order to make this a fair game is [tex]27\div 35[/tex]

Calculation of the number of points:

Since  If a player rolls doubles, the player earns 3 points and gets another roll. If the player rolls doubles again, the player earns 9 more points.

So here the probabilities could be

one double= [tex]5\div 36[/tex]

two doubles [tex]=1\div 36[/tex]

no doubles =[tex]1\div6[/tex]

Now

here we assume the number of points be x

So,

[tex]12\div 36 + 5[(3-x)\div 36] - (5)(x\div 6) = 0\\\\x=27\div 35[/tex]

Therefore, The number of points that  should the player lose for not rolling doubles in order to make this a fair game is [tex]27\div 35[/tex]

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