Secants PR and TR intersect outside of a circle. QS measures 70.15° and ∠ QRS measures 51.68°. Determine the measure of PT.

Answer:
173.51
Step-by-step explanation:
[tex] \frac{pt - 70.15}{2} = 51.68[/tex]
[tex]pt - 70.15 = 103.36[/tex]
[tex]pt = 173.51[/tex]