Answer:
The correct answer would be :
rr (parent I) × rr (parent II)
Explanation:
In this given question there are two traits present in the corns that are red kernels and yellow kernels. It is also given that the yellow kernel is dominant over the yellow kernels.
In the provided Punnett square and on our knowledge we know that the recessive trait which is the yellow kernel only expresses itself when both the genes of the kernel have recessive gene r.
In the heterozygous cross, there would be only 50% chances of the kernels of an ear of corn to produce yellow kernels.. There is only one possible condition which is:
rr cross with rr
r r
r rr rr
r rr rr
All kernels in this condition will be yellow.
