since the equation for both triangles have A^2 + B^2 you can think of the two equations for C^2 and n^2 as a system of equations such as to what a equals in the first equation for A^2 + B^2 in the second question after you substitute to what equation do you get

As per the Pythagoras theorem, It defined that the area of the square i.e. hypotenuse is equivalent to the sum of the areas of the squares on the other two sides.

So based on this, we can considered the following equations:

Since

a² + b² = c²

a² + b² = n²

So here

a² + b² = n²

c² = n²

c = n

Therefore we get the new equation as c = n

Learn more about an equation here: https://brainly.com/question/24705024

since the equation for both triangles have A^2 + B^2 you can think of the two equations for C^2 and n^2 as a system of equations such as to what a equals in the first equation for A^2 + B^2 in the second question after you substitute to what equation do you get ​

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Calculation of the new equation:

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since the equation for both triangles have A^2 + B^2 you can think of the two equations for C^2 and n^2 as a system of equations such as to what a equals in the first equation for A^2 + B^2 in the second question after you substitute to what equation do you get