Respuesta :
The given question is incomplete. The complete question is:
A chemist prepares a solution of mercury(I) chloride [tex]Hg_2Cl_2[/tex] by weighing out 0.537 mg of mercury(I) chloride into a 400. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's mercury(I) chloride solution. Round your answer to 3 significant digits
Answer: The concentration in g/dL of the chemist's mercury(I) chloride solution is [tex]1.34\times 10^{-4}[/tex]
Explanation:
Concentration of a solution is defined as how many grams of solute in=s dissolved in a particular amount of solvent.
Given : Â mass of mercury (I) chloride = 0.537 mg = [tex]5.37\times 10^{-4}g[/tex] Â Â Â [tex](1mg=0.001g)[/tex]
Volume of solution = 400 ml = 4 dL Â Â (1ml=0.01dL)
Thus concentration of mercury (I) chloride in g/dL is = [tex]\frac{5.37\times 10^{-4}g}{4dL}=1.34\times 10^{-4}g/dL[/tex]
The concentration in g/dL of the chemist's mercury(I) chloride solution is [tex]1.34\times 10^{-4}[/tex]
