John's full backpack weighs 5 1/2 pounds, and Tyrone's full backpack weighs 6 3/5 pounds. What is the total weight of both boys' backpacks?

Respuesta :

Answer: [tex]\dfrac{121}{10}\ \text{Pounds}[/tex]

Step-by-step explanation:

Given

The weight of John's backpack is

[tex]5\ \dfrac{1}{2}=\dfrac{5\times 2+1}{2}=\dfrac{11}{2}\ \text{Pounds}[/tex]

Weight of Tyrone's backpack is

[tex]6\ \dfrac{3}{5}=\dfrac{6\times 5+3}{5}=\dfrac{33}{5}\ \text{Pounds}[/tex]

Combined Weight of two

[tex]\Rightarrow \dfrac{11}{2}+\dfrac{33}{5}=\dfrac{11\times5+33\times 2}{10}\\\Rightarrow \dfrac{121}{10}\ or\ 12\ \dfrac{1}{10}\ \text{Pounds}[/tex]

the total weight of the boy's backpack is 121/10

the first step is to convert the fraction from mixed fraction to proper fraction

5 1/2

= 11/2

6 3/5

= 33/5

the total weight of the boys can be calculated as follows

= 11/2 + 33/5

= 55 + 66/10

= 121/10

Hence the total weight of the boy's backpack is 121/10

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