___________________________________
[tex]\huge\underline{\tt{\red{Formula:}}}[/tex]
[tex]\quad\quad\quad\quad\tt{density = \frac{mass}{volume} }[/tex]
[tex]\huge\underline{\tt{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\tt{density = \frac{7.0 \times {10}^{24} \: kg}{3.5 \times {10}^{12} \: k {m}^{3} } }[/tex]
[tex]\quad\quad\quad\quad\tt{density = (\frac{7.0}{3.5 } = 2.0)}[/tex]
[tex]\quad\quad\quad\quad\tt{\:\:and\:\:({10}^{24 -12})}[/tex]
[tex]\quad\quad\quad\quad \boxed{\tt{density = 2.0 \times {10}^{12} \: \frac{kg}{k {m}^{3} }} }[/tex]
[tex]\huge\underline{\tt{\red{Answer:}}}[/tex]
[tex]\quad\quad \underline{\boxed{\tt{ \red{B.) \: \: 2.0 \times {10}^{12} \: \frac{kg}{k {m}^{3} }}}} }[/tex]
[tex]\huge\underline{\tt{\red{Explanation:}}}[/tex]
Given that the formula for density is equal to mass all over the volume.
We use this formula:
[tex]\boxed{\tt{density = \frac{mass}{volume} }}[/tex].
We substitute it like this:
[tex]\boxed{\tt{density = \frac{7.0 \times {10}^{24} \: kg}{3.5 \times {10}^{12} \: k {m}^{3} } }}[/tex]
Then, hence we got:
[tex]\boxed{\tt{density = 2.0 \times {10}^{12} \: \frac{kg}{k {m}^{3} }} }[/tex]
___________________________________
#CarryOnLearning
✍︎ C.Rose❀
