Respuesta :
Answer:
x + 3
Step-by-step explanation:
Since x > 5, then x + 3 > 0 and Ix + 3I = x + 3
The Simplify value of [tex]|x+3|[/tex], if [tex]x > 5[/tex] without using the absolute value sign is [tex]6[/tex].
What is absolute value sign ?
The absolute value (or modulus) | x | of a real number x is the non-negative value of x without regard to its sign.
We have,
[tex]|x+3|[/tex], if [tex]x > 5[/tex]
Note that, if [tex]x > 5[/tex] , then [tex]x+3 > 3+5=8[/tex]
Then [tex]x+3 > 0[/tex]
Recall that the absolute value function is defined as
[tex]|x|=x[/tex] , if [tex]x\geq 0[/tex]
And,
[tex]|x|= -x[/tex] if [tex]x < 0[/tex],
So,
As mentioned above [tex]x+3 > 0[/tex],
Then [tex]|x+3|=x+3[/tex]
As given [tex]x > 5[/tex] , so choose any value of [tex]x[/tex] which after adding to [tex]x+3[/tex], we get more than [tex]5[/tex],
i.e.
[tex]x[/tex] can be [tex]3,4,5,6,7........[/tex].
Let's
[tex]x=3[/tex]
We get ,
[tex]x+3=3+3=6[/tex] which shows that [tex]x > 5[/tex] .
Hence, we can say that the Simplify value of [tex]|x+3|[/tex], if [tex]x > 5[/tex] without using the absolute value sign is [tex]6[/tex].
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