Answer:
Step-by-step explanation:
By applying Pythagoras theorem in ΔEGD,
ED² = EG² + GD²
y² = 5² + 2²
y = √29
y = 5.39
By applying cosine rule in ΔBCD,
cos(28.3)° = [tex]\frac{x}{19}[/tex]
x = 19cos(28.3)
x = 16.73"
Area of ABCDE = Area of trapezoid ABDE + Area of triangle BCD
= [tex]\frac{1}{2}(15+19)5+\frac{1}{2}(16.73)(9)[/tex]
= 85 + 75.28
= 160.28 square inch
Perimeter of ABCDE = AB + BC + CD + DE + AE
= 5.39 + 16.73 + 9 + 5.39 + 15
= 51.51"
