Answer: 0.1
Step-by-step explanation:
Given
Bag-I has 2 blue,3 orange, 5 red
Bag-II has 4 Pink,10 blue, 6 brown
No of ways of choosing a blue marble from bag-I
[tex]\Rightarrow ^2C_1[/tex]
Total no of ways of choosing a marble from bag-I
[tex]\Rightarrow ^{10}C_1[/tex]
No of ways of choosing a blue marble from bag-II
[tex]\Rightarrow ^{10}C_1[/tex]
Total no of ways of choosing a marble from bag-II
[tex]\Rightarrow ^{20}C_1[/tex]
The probability that he will pull out a blue marble from each bag is
[tex]\Rightarrow P=\text{Probability of pulling a blue marble from bag-I}\times \text{Probability of pulling a blue out bag-II}[/tex]
[tex]\Rightarrow P=\dfrac{^2C_1}{^{10}C_1}\times \dfrac{^{10}C_1}{^{20}C_1}\\\\\Rightarrow P=\dfrac{2}{10}\times \dfrac{10}{20}=\dfrac{1}{10}[/tex]