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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.
The magnitude of q1 is 3 times the magnitude of q2. At which point a on the axis is the
electric field zero?
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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis The magnitude of q1 is 3 times the magnitude of q2 At which point a on the class=

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abhi569

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

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