Answer:
The answer is option A
Explanation:
why?
because to get the power, you need this equation. P= Work done/Time taken.
the unit of time are seconds, and the unit of work is kJ. So, the equation is=
360kJ/120s = 3kW
The useful power output of the crane is: A. 3.0 kW.
Given the following data:
To find the useful power output of the crane:
First of all, we would convert the time in minutes to seconds.
Conversion:
1 minutes = 60 seconds
2 minutes = 120 seconds.
360 kJ = 360,000 Joules.
Mathematically, the power output of a device is given by the formula;
[tex]Power = \frac{Energy}{Time} \\\\Power = \frac{360,000}{120}[/tex]
Power output = 3000 Watts
In kilowatts, power output = 3.0 kW
Therefore, the useful power output of the crane is 3.0 kW.
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