Answer:
M is perpendicular to K
Step-by-step explanation:
Given the equations of the following line
K: x+2y=6
P: 6x + 3y=12
M: -x+ 2y=10
First we need to get the slpe of each line as shown;
For K:
K: x+2y=6
Rewrite in standard form;
2y = -x + 6
y = -1/2 x + 6/2
y = -1/2 + 3
Slope of K is -1/2
For P:
P: 6x + 3y=12
Rewrite;
3y = -6x + 12
y = -6/3 x + 12/3
y = -2x + 4
Slope of P is 2
For M;
M: -x+ 2y=10
Rewrite
2y = x + 10
y = 1/2 x + 10/2
y = 1/2 x + 5
Slope of M is 1/2
Taking the product of slope K and P
Mk * Mp = -1/2 * 2
Mk * Mp = -1
Since the slope of K and P is -1, hence line M and line P are perpendicular
