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To launch a ball, a pinball machine compress a spring 4.0 cm. The spring constant is 13 N/M. What is the force of the spring on the ball when the spring is released?

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OverpoweredNoob

Answer:

0.52 N

Explanation:

k = 13 N/m

x = 0.04 m

Plug those values into Hooke's Law:

F = kx

F = (13 N/m)(0.04 m)

F = 0.52 N

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