a 4000 pound car driving at 40 miles/hour has how many times the kinetic energy of another 4000 pound car driving at 10 miles/hour.

Answer = 400 I think
Explain = do 4,000 five by 40 then get a answer of 100 and then do 4,000 divid by 10 and get 400 do you see the similarities of both of these question they are the same question but just written in different ways just by adding a zero.

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boffeemadrid boffeemadrid · Answer 2 · 2022-04-20T12:01:18+02:00

The comparison of the kinetic energy of the given bodies is required.

The first car has 16 times more the kinetic energy of the second car.

Kinetic energy

m = Mass of car = 4000 pound

[tex]v_1[/tex] = Initial velocity of car = 40 miles/hour

[tex]v_2[/tex] = Final velocity of car = 10 miles/hour

The mass of the car is constant so we have the relation

[tex]K\propto v^2[/tex]

Thus,

[tex]\dfrac{K_1}{K_2}=\dfrac{v_1^2}{v_2^2}\\\Rightarrow K_1=K_2\dfrac{40^2}{10^2}\\\Rightarrow K_1=16K_2[/tex]

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