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A box contains 13 transistors, 3 of which are defective. if 3 are selected at random, find the probability that

a. All are defective
b. None are defective

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auniquestyle
I would think none since the amount of good are so high. Hope this helped good luck.

The probability of getting All defective transistors is  [tex]\frac{3}{13}[/tex] = 0.23

and The probability of getting no defective transistors is  [tex]\frac{10}{13}[/tex] = 0.769

What is probability?

Many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur.

[tex]Probability=\frac{Number\ of\ favourable\ conditions}{total\ number of conditions}[/tex]

Given

Total number of transistor are 17, and 3 transistor are defected.

[tex]Probability=\frac{Number\ of\ favourable\ conditions}{total\ number of conditions}[/tex]

So the probability of getting All are defective = [tex]\frac{3}{13}[/tex] = 0.23

And The probability of getting no defective transistors is  [tex]\frac{10}{13}[/tex] = 0.769

Hence, The probability of getting All defective transistors is  [tex]\frac{3}{13}[/tex] = 0.23

and The probability of getting no defective transistors is  [tex]\frac{10}{13}[/tex] = 0.769

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