A once thriving company in Teaneck had its monthly profits, in thousands of dollars, modeled by the equation?
f(t) = t^2 + 9/ 1t^2 + 2

where t is in months after June 1st, 2002.

Estimate the company's profits on June 1st, 2002.
Estimate the company's profits many years into the future

Respuesta :

- The company`s profits on June 1st, 2002:
t = 0
f ( 0 ) = ( 0² + 9 ) / ( 0² + 2 ) = 9/2 = 4.5 ( or $4,500 )
- The company`s profits many years into the future:
[tex] \lim_{t \to \infty} \frac{ t^{2}+9}{ t^{2} +2}= \\ = \lim_{t \to \infty} \frac{2t}{2t} = 1 [/tex]
( or  $1,000 )

Answer:

1) 4.5%    2)1%

Step-by-step explanation:

Given equation The monthly profits: [tex]f(t) = \frac{t^2 + 9}{t^2 + 2}[/tex]

where t is in months after june 1st,2002

To find : The company's profits on June 1st, 2002

which means t=0

⇒ [tex]f(0) = \frac{0^2 + 9}{0^2 + 2}[/tex]

⇒ [tex]f(0) = \frac{9}{2}[/tex]

⇒ [tex]f(0) = 4.5[/tex]  

The company's profits on June 1st, 2002 = 4.5%

To find :The company's profits many years into the future

we take limit tends to infinity

[tex]\lim_{n \to \infty}( \frac{t^2 + 9}{t^2 + 2})[/tex]

[tex]\lim_{n \to \infty}( \frac{2t}{2t})=1[/tex]

The company's profits many years into the future = 1%