First, since the snake is travelling at a constant velocity, find out how long it takes the snake to go 45m (you have a 5m head start).
45m1.5m/s=30s
Now you just need to go your 40 meters in that amount of time:
Xf−Xi=1/2(Vi+Vf)t
40m−0m=1/2(0+Vf)(30s)40m∗230s=Vf=223m/s Since you're starting from rest, your average speed must be half of that which is 113m/s
So at 40m, you and the snake will be at the same point however you will be going 223m/s at that point so the snake cannot overtake you.
Looking back at the question, I believe it wants to know what your average speed needs to be...which is:>113m/s
