In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.18 m. The mug slides off the counter and strikes the floor 1.20 m from the base of the counter. With what velocity did the mug leave the counter? What was the direction of the mug's velocity just before it hit the floor?

Respuesta :

The first thing you need to find is the time it took to fall. This time is independent of the mug's horizontal velocity. remember that the mug has 0 initial velocity in the y direction so the time is found fromD=1/2∗g∗t square =1.18The initial velocity will be 1.2/t
 When the mug hits the floor it will have the same x velocity as when it left the table. The y velocity will be v=g*t.
 You can find the direction of the velocity vector from trigonometryθ=tan elevated  to −1(vy/vx)
I think this can help you a lot 

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