A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest.
1)How fast is the mass moving at the bottom of its path?2)What is the magnitude of the tension in the string at the bottom of the path?

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21-11-2016
Physics

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A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest.
1)How fast is the mass moving at the bottom of its path?2)What is the magnitude of the tension in the string at the bottom of the path?

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syed514 syed514 · Answer 1 · 2016-11-21T20:18:31+01:00

syed514 syed514

21-11-2016

ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.

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A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest. 1)How fast is the mass moving at the bottom of its path?2)What is the magnitude of the tension in the string at the bottom of the path?

Respuesta :

Otras preguntas

A mass m = 4.6 kg hangs on the end of a massless rope L = 2.16 m long. The pendulum is held horizontal and released from rest.
1)How fast is the mass moving at the bottom of its path?2)What is the magnitude of the tension in the string at the bottom of the path?