Suppose a treadmill has an average acceleration of 4.7 x 10^-3. A) how much does its speed change after five min? B )If the treadmill's initial speed is 1.7 m/s ,what will it's final speed be?

Respuesta :

v1 - v0  = at

= 4.7  x 10^3 m/s^2 x 300s

= 1.4 x 10^6 m/s

hope this helps

Explanation:

Given that,

Acceleration of the treadmill, [tex]a=4.7\times 10^{-3}\ m/s^2[/tex]

Time, t = 5 min = 300 s

Acceleration is given by :

[tex]a=\dfrac{v-u}{t}[/tex]

(a) (v-u) is the change in speed.

[tex]v-u=a\times t[/tex]

[tex]v-u=4.7\times 10^{-3}\times 300[/tex]  

[tex]v-u=1.41\ m/s[/tex]

So, the change in speed of the treadmill is 1.41 m/s.      

(b) Initial speed of the treadmill, u = 1.7 m/s

The final speed is given by using equation as :

[tex]v=u+at[/tex]

[tex]v=1.7+4.7\times 10^{-3}\times 300[/tex]

v = 3.11 m/s

Hence, this is the required solution.