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For the following metal and non-metal combination reaction you have 3 moles of Na. How many moles of Cl2 would you need to add to have stoichiometrically equivalent amounts of NA and Cl2?

2Na(s) + Cl2(g) --> 2NaCl(s)

Respuesta :

scme1702
The molar ratio of Na : Cl₂ is 2:1
Moles of Na present = 3
2/1 = 3/x
x = 1.5
1.5 moles of Cl₂ needed to have stoichometrically equivalent amount