The answer is 60.
Let A be the number of radios with digital tuners and let B be the number of radios with CD players.
The total number of radios is A∪B. It consists of both A radios and B radios, but however, radios with both digital tuners and CD players (A∩B) must be excluded from that number (either way they will be counted twice):
A∪B = A + B - A∩B
A∪B = 100
A = 70
B = 90
A∩B = ?
100 = 70 + 90 - A∩B
100 = 160 - A∩B
A∩B = 160 - 100
A∩B = 60