Respuesta :
using a right triangle formed by boat with base and top of lighthouse.Note: 15 minutes = 0.25 degreesLet d be distance the boat is from shore.tan(90−13.25)=d/175
d=175∗tan(76.75)=743.2
d=175∗tan(76.75)=743.2
Answer:
743.41 feet.
Step-by-step explanation:
In this question it is given that height of the tower OS is 175 feet and angle of depression ∠ASB = 13°15'
angle of depression to the boat B will be equal to the angle of elevation "∠B"
Now ∠ASB = 13°15' ≈ 13° + [tex](\frac{15}{60})[/tex]°
= 13° + (0.25)°
= 13.25°
Now tan ∠B = [tex]\frac{SO}{OB}[/tex]
tan (13.25) = [tex]\frac{175}{x}[/tex]
x = [tex]\frac{175}{0.2354}[/tex]
= 743.41 feet.
Motorboat is 743.41 feet far from the shore.
