Answer:
Length of the conjugate axis is 6 units.
Step-by-step explanation:
Given Equation is ,
[tex]\frac{(x-1)^2}{25}-\frac{(y+3)^2}{9}=1[/tex]
To find: Length of the conjugate axis.
We know that given equation is Equation of Hyperbola.
First Transverse Axis: Axis passing through the vertices is called the transverse axis. Length of the transverse axis is 2a.
Now, Conjugate Axis: Axis which is perpendicular to the transverse axis through the center is called the conjugate axis. Length of the Conjugate axis is 2b.
Equation in standard form is written as ,
[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1[/tex]
So, Comparing with Standard equation,
we get, a² = 25 ⇒ a = 5 and b² = 9 ⇒ b = 3
Thus, Length of the conjugate axis = 2 × 3 = 6 unit
Therefore, Length of the conjugate axis is 6 units.
