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21-11-2016
Mathematics

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Prove the trigonometric identity:
(csc^2x)/(cotx)=cscxsecx ...?

Respuesta :

Nirina7 Nirina7

22-11-2016

cscx = 1 / sinx, so csc^2x = 1/ sin²x, and cotx=cosx / sinx
so (csc^2x)/(cotx)=(1/ sin²x) (sinx/cosx) = 1/(sinxcosx) = 1/sinx 1/cosx
finally
(csc^2x)/(cotx)=cscxsecx

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