Respuesta :
f(x)=x+3; g(x)=1/x^2
If you take B f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula (in other words, f(x) becomes the x for g) g(x)=1/x^2 g(x)=1/(x+3)^2
If you take B f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula (in other words, f(x) becomes the x for g) g(x)=1/x^2 g(x)=1/(x+3)^2
I am pretty sure that the only possibl decomposition of the finction represented above is being revealed by the second option - B. f(x)=x+3; g(x)=1/x^2. I choose this one because I plugged the f(x) into the g(x) and that's what I got :[tex]g(x)=1/x^2
g(x)=1/(x+3)^2[/tex]