Determine whether the infinite geometric series is convergent or divergent. If it is convergent, find its sum. (If the series is divergent, enter DIVERGENT.)
The geometric series can be rewritten as 1 + (-1/6) + (-1/6)^2 + (-1/6)^3 + ... Since the magnitude of the common ratio is less than 1. The series is then convergent and it has a sum. S = a/(1-r) = 1/(1+1/6) = 6/7
