Respuesta :
Let c is the cost of renting a canoe and t is the cost of renting inner tubes.
For the girls,
2c + 3t = 80
For the boys,
c + 7t = 95
Solving the system of equations, multiply the second equation by 2 and subtract them.
2c + 3t = 80
2c + 14t = 190
---------------
11t = 110
t = 10
Substitute t to either equations,
c = 95 - 7t
c = 95 - 7(10)
c = 25
Therefore, one canoe costs $25 (C.)
For the girls,
2c + 3t = 80
For the boys,
c + 7t = 95
Solving the system of equations, multiply the second equation by 2 and subtract them.
2c + 3t = 80
2c + 14t = 190
---------------
11t = 110
t = 10
Substitute t to either equations,
c = 95 - 7t
c = 95 - 7(10)
c = 25
Therefore, one canoe costs $25 (C.)
The cost to rent 1 canoe from the rent made by the group of the girls and boys is $25.
What are word problems?
Word problems are a mathematical interpretation by using variables, numbers, and arithmetic operations to solve real-life problems.
From the given information:
- The group of girls: 2c + 3t = 80 --- (1)
- The group of boys: 1c + 7t = 95 ---- (2)
Now, we can have a system of equations, and we can solve for the number of canoes and the inner tubes rented.
Using Elimination method:
2c + 3t = 80 --- × (1)
c + 7t = 95 --- × (2)
2c + 3t = 80
-2c + 14t = 190
0 + -11t = -110
-11t = -110
t = -110/-11
t = 10
From equation (1)
2c + 3t = 80
2c + 3(10) = 80
2c + 30 = 80
2c = 80 - 30
2c = 50
c = 50/2
c = 25
Therefore, we can conclude that the cost of the rent of 1 canoe is $25.
Learn more about word problems here:
https://brainly.com/question/21405634
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