The area of the sector of the circle whose radius is 4.2 cm while the angle made at the center is 68° is 10.5 cm².
A circle can be defined as a shape that consists of all points in a plane that are at equal distance from a given point, therefore, the center.
As it is given that the length of the radius of the circle is 4.2 cm, while the angle made by the sector at the center of the circle is 68°. Therefore, the area of the sector of the circle can be written as,
[tex]\text{Area of the sector of the circle} = \pi r^2\times \dfrac{\theta}{360^o}[/tex]
Substituting the value, we will get,
[tex]\text{Area of the sector of the circle} = \pi \times(4.2^2)\times \dfrac{68^o}{360^o}[/tex]
[tex]= 10.472 \approx 10.5\rm\ cm^2[/tex]
Hence, the area of the sector of the circle whose radius is 4.2 cm while the angle made at the center is 68° is 10.5 cm².
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