Respuesta :
Below are the answers:
a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page atthe bottom
V=-Δφ/ Δt = -B·ΔA/ Δt
b. As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radiallyoutward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law
F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvBˆ
Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because theforce is pointing into the center of the loop, we know we have positive current at that point (into the page).
a. There is a constant magnetic Feld, which means B is constant, so we can rewrite the change in fux as above.Because ΔA is positive, there will be a negative emf in the loop, corresponding to an induced magnetic momentpointing to the left on the page. The current in the loop will be into the page at the top and out of the page atthe bottom
V=-Δφ/ Δt = -B·ΔA/ Δt
b. As the loop’s radius is increasing, we can think about individual electrons in the wire loop as moving radiallyoutward. We’ll consider one in the top of the loop (which is moving up the page). Using the Lorentz ²orce Law
F=q(~v⇥~B)=qvB(ˆy⇥ˆx)=-qvBˆ
Constant forces pointing into the center of the loop will result in circular orbits (around the wire). Because theforce is pointing into the center of the loop, we know we have positive current at that point (into the page).
The current in the loop will be into the page at the top and out of the page that the bottom.
What is a solenoid?
A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil.
A). Because there is a constant magnetic Feld, B is constant, and we can recast the change in flux as shown above. Because A is positive,
The loop will have a negative emf, corresponding to an induced magnetic moment pointing to the left on the page. The loop's current will flow into the page at the top and out of the page at the bottom.
B) Individual electrons in the wire loop can be thought of as migrating radially outward as the radius of the loop increases.
We'll think about one at the top of the loop (which is moving up the page). Using Lorentz's force Law;
The force is obtained as;
F=qvB
Hence the current in the loop will be on the page at the top and out of the page that the bottom.
To learn more about the solenoid refer to the link ;
brainly.com/question/16015159
