Respuesta :

miriyu
first, you'll probably want to get it into slope-intercept form because that's what we're more familiar with graphing

y - 5 = (4/3)(x - 5) ... 
y - 5 = (4/3)x - (20/3) ... distributed (4/3)
y = (4/3)x - 5/3 ... added 5 to both sides

so that's your slope-intercept form. (-5/3) in decimal form is 1.6666, so you'll graph a point a little over halfway past -1 on the y-axis, because it's your y-intercept

from there, you actually don't need points. you can just use the "rise over run" method for your slope and go up 4 from y = -1.66, then over 3. but, just so you can have some peace of mind, plugging in points is pretty simple from there.

y = (4/3)x - 5/3

when x = 1...
y = (4/3)1 - (5/3)
y = -1/3
(1, -1/3)

when x = -1...
y = (4/3)(-1) - (5/3)
y = -3
(-1, -3)

when x = 3...
y = (4/3)3 - (5/3)
y = 2.333
(3, 2.33)

i don't know how many points you need, but 3 plus your y-intercept should be enough to get you a decent graph.