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Which product of prime polynomials is equivalent to 8x3 – 2x?
x(2x – 1)(2x – 1) 2x(x + 1)(x – 1) 2x2(2x + 1)(2x – 1) 2x(2x + 1)(2x – 1)

Respuesta :

texaschic101
2x(2x + 1)(2x - 1) =
2x(4x^2 - 1) =
8x^3 - 2x

Answer:

  2x(2x+1)(2x-1)  

Step-by-step explanation:

We have been given the polynomial

[tex]8x^3-2x[/tex]

We will take common factor out which is 2x

[tex]2x(4x^2-1)[/tex]

Now, using[tex]a^2-b^2=(a+b)(a-b)[/tex]

[tex]a=2x\text{and}b=1[/tex]

[tex]4x^2-1=(2x-1)(2x+1)[/tex]

So, given polynomial is equivalent to: 2x(2x+1)(2x-1)

Therefore, last option is correct.

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