Answer:
The Alkane formed is 5,5-dibromo-2,2,3-trimethylhexane. as shown below in attached scheme (Green Color).
Explanation:
Alkynes like Alkenes undergo Electrophillic Addition Reactions. The reaction given is a two step reaction. In step 1, the Alkyne adds first equivalent of HBr obeying Markovnikov's rule (i.e. Bromine will add to carbon containing less number of hydrogen atoms) and forms 2-bromo-4,5,5-trimethylhex-1-ene. In step 2, the alkene formed in first step (2-bromo-4,5,5-trimethylhex-1-ene) undergoes addition reaction with the second equivalent of HBr via Markovnikov's rule to produce 5,5-dibromo-2,2,3-trimethylhexane.
The scheme is attached below, Blue color is assigned to starting Alkyne, Red color is assigned to intermediate Alkene and Green color is assigned to product Alkane respectively.
