When movies are being created, the set designers often use miniature models before they create the actual movie set. The set designers for Jurassic Park 3, created a 6 inch high and 4 inch long model dinosaur that represented a 20 feet high dinosaur on the set. How long was the actual dinosaur, rounded to the nearest foot?
A. 15 feet
B. 13 feet
C. 14 feet
D. 12 feet

Respuesta :

the actual dinosaur, rounded to the nearest foot was :
we have to made cross multiply

6x = 20*4
x = 80/6
x = 13 approximately

hope this help

Answer:

B. 13 Feet

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

Before we can solve this question we need to turn the 20 feet of the height of the dinosaur on set into inches. Since there are 12 inches in one foot we multiply 20 by 12.

[tex]20*12 = 240 in[/tex]

Now  since we are given 3 value with 1 variable, and the problem is a ratio problem. Then we can use the Rule of Three technique to solve for the length of the dinosaur. This technique as shown in the picture below would be the following...

   6 in high   ⇔   4 in long

240 in high   ⇔   x

[tex]\frac{240*4}{6} = x[/tex]

[tex]160in = x[/tex]

[tex]\frac{160in}{12} = 13.33ft[/tex] .... turn length from inches into feet

Finally, we can see that the length of the dinosaur is 13 ft (rounded to the nearest foot).

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