contestada

Approximate to the nearest tenth the real zeros of f(x) = –5x3 + 9x2 + 12x + 2.

answers:
The zeros are approximately 0.2, 0.7, and 2.7.
The zeros are approximately –2.7, –1.7, and 0.2.
The zeros are approximately –0.2, –0.7, and 2.7.
The zeros are approximately –0.5, –0.7, and 1.7.

Respuesta :

Correct answer is C.

[tex]-5 x^3 + 9 x^2 +12 x+ 2=(-5 x-1) \left(x^2-2 x-2\right) \\ \\\left\{-\frac{1}{5},1-\sqrt{3},1+\sqrt{3}\right\}\to \{-0.2,-0.732051,2.73205\}[/tex]

Or check if f(0.2) = 0 to eliminate A and B.
Then check if f(-0.5) = 0 to eliminate D.
anbundy

Answer:

the answer is C

Step-by-step explanation: