Respuesta :
[tex]Q = abt = a(1 + r)^t
\\Q=79(1.002)^t
\\Q=79(1+0.002)^t
\\
\\r=0.002\times 100\%=0.2\%[/tex]
Answer: r as a percent will be equal to 0.2%.
Step-by-step explanation:
It is given that Q = [tex]ab^{t}[/tex] = [tex]a(1 + r)^{t}[/tex] ........... (1)
Also, Q = [tex]79(1.002)^{t}[/tex] .......... (2)
Thus, equating both equations (1) and (2), we will get the equation as follows.
[tex]a(1 + r)^{t}[/tex] = [tex]79(1.002)^{t}[/tex] ........ (3)
Therefore, from equation (3) we can conclude that the value of a = 79 and (1 + r) = 1.002
Since, 1 + r = 1.002
thus, r = 1.002 - 1
r = 0.002
Now, convert 0.002 into fraction form as follows.
[tex]\frac{2}{1000}[/tex]
Therefore, r as a percent will be as follows.
[tex]\frac{2}{1000}[/tex] × 100%
Hence, r as a percent will be equal to 0.2%.
