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Two 125 kg bumper cars are moving toward each other in opposite directions. Car X is moving at 10 m/s and Car Z at –12 m/s when they collide head–on. If the resulting velocity of Car Z after the collision is 10 m/s, what is the velocity of Car X after the collision?

–12 m/s

–10 m/s

10 m/s

12 m/s

Respuesta :

scme1702
Applying the law of conservation of momentum,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂; m₁ = m₂ so:
u₁ + u₂ = v₁ + v₂

10 - 12 = v₁ + 10
v₁ = -12 m/s

Answer:

A

Explanation:

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