Radon-222 is a radioactive gas with a half-life of 3.82 days. How long would it take for fifteen-sixteenths of a sample of radon-222 to decay?
15.28 days
30.56 days
45.84 days
49.66 days

Respuesta :

Use the formula in terms of half life from the normal exponential functions 

N(t) = N(0) (1/2) ^ (t/thalf) 


N(0) is the original quantity 


N(t) = quantity remaining at time t 


t is the time 



thalf is half life 


1/16 = (1/2)^(t/3.82) 


16 = 2^(t/3.82) 


4 = t/3.82 


t = 15.28 days

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