Given a regular square pyramid with RS = 6 and PX = 4, find the following measure.
PY =

Answer:
[tex]PY=5\ units[/tex]
Step-by-step explanation:
we know that
Applying the Pythagoras Theorem
[tex]PY^{2}=PX^{2}+XY^{2}[/tex]
In this problem we have that
[tex]XY=RS/2=6/2=3\ units[/tex]
[tex]PX=4\ units[/tex]
substitute
[tex]PY^{2}=4^{2}+3^{2}[/tex]
[tex]PY^{2}=25[/tex]
[tex]PY=\sqrt{25}\ units[/tex]
[tex]PY=5\ units[/tex]
Answer:
PY=5.
Step-by-step explanation:
In triangle PXY it is given PX=4, XY=half of RS=6÷2=3.
Two of the sides known we can find the third side using Pythagorean Theorem:
[tex]PY^{2} =PX^{2} +XY^{2}[/tex]
Or, [tex]PY^{2} =4^{2}+3^{2} =16+9=25.[/tex]
Taking root of both sides PY=5.