Respuesta :
The solution to the problem is as follows:
If you use Ln you can get rid of e.
ln(e^0.4x) = ln(0.4)
0.4x = ln(0.4)
x = (ln(0.4))/0.4
x = -2.29
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
If you use Ln you can get rid of e.
ln(e^0.4x) = ln(0.4)
0.4x = ln(0.4)
x = (ln(0.4))/0.4
x = -2.29
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
x = ( -2.29 )
Step-by-step explanation:
The given expression is [tex]e^{(0.4x)}=0.4[/tex]
We have to solve this equation for the value of x. We take natural log on both the sides of the equation.
[tex]ln(e)^{0.4x}=ln(0.4)[/tex]
0.4x ln(e) = ln (0.4)
0.4x = ln (0.4) [ Since lne = 1 ]
0.4x = -0.9163
[tex]x=\frac{0.9163}{0.4}[/tex] = 2.29
Therefore, x = ( -2.29 ) is the answer.